Question

Calculate self inductance of a plane coil of radius 2 cm having total no of turns as 50.

Answer 1

Answer:

0.004 v

Explanation:

Given that,

Number of turns N=50

Magnetic field B1=2T

Magnetic field B2=4T

Time t=3.14s

Radius r=2cm

Now, the induced e. m. f in coil

  e=dt−N(B2−B1)Acosθ

 e=3.14−50(4−2)3.14×(2×10−2)2cos00

 e=3.14−50×2×3.14×4×10−4

 ∣e∣=0.04V

Hence, the induced e. m. f is 0.04 V

Answer 2

$\pi \times 4 \\ \\ 6.2 \\ \\ 50 \times 6.2 \\ \\ 3100cm$