Calculate series limit of lyman series if r is 1.1×10^7
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Answer:
1λ=R(1(n1)2−1(n2)2)⋅Z2
where,
R = Rydbergs constant (Also written is RH)
Z = atomic number
Since the question is asking for 1st line of Lyman series therefore
n1=1
n2=2
since the electron is de-exited from 1(st) exited state (i.e n=2) to ground state (i.e n=1) for first line of Lyman series.
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Therefore plugging in the values
1λ=R(1(1)2−1(2)2)⋅12
Since the atomic number of Hydrogen is 1.
By doing the math, we get the wavelength as
λ=43⋅912.A
since 1R=912.A
therefore
λ=1216.A
or
λ=121.6nm
Explanation:
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