Calculate sigma and z for 3d electron in mn (z=25)atom
Answers
Answer:
Explanation:
where:
Z* = effective nuclear charge
Z = atomic number of Cr = 24
S = shielding
Let us first calculate S using Slater's rule.
*Write the electronic configuration as follows: (1s)^2 (2s 2p)^8 (3s 3p)^8 (3d)^5 (4s)^1
*Electrons in an "s" or "p" orbit in the same shell as the electron for which you're solving contribute 0.35, electrons in an "s" or "p" orbital in the shell one energy level lower contribute 0.85, and electrons in an "s" or "p" orbital in shells two energy levels and lower contribute 1.
Therefore, the (4s)^1 do not contribute since we are focusing on the 3d orbital. Therefore,
S = (5 x 0.35) + (8 x 0.85) + (10 x 1) = 18.55
Thus,
Z* Z - S = 24 - 18.55 = 5.45
* Electrons in a "d" or "f" orbital in the same shell as the electron for which you're calculating contribute 0.35, and electrons in an "d" or "f" orbital in all lower energy levels contribute 1. Electrons in shells higher than the electron for which you're solving do not contribute to shielding.
Therefore, the (4s)^1 do not contribute since we are focusing on the 3d orbital. Therefore,
S = (4 x 0.35) + (18 x 1) = 19.4
Thus,
Z* = 24 - 19.4 = 4.6