Question

Calculate sin A , tan A and cos²A+sin²A if base is a and perpendicular is a

Answer 1

AnSwEr-

By Pythagoras Theoram,

$(AB)^2+(BC)^2=(AC)^2$

Therefore,

$a^2+a^2=AC^2$

Now,

$2a^2=AC^2\\=>\sqrt{2a^2}=AC\\AC=a\sqrt{2}$

Now, we have

AB= a

BC= a

AC= a√2

◆To find:-

(i) Sin A

$Sin=\frac{Opposite}{Hypotenuse}\\=>\frac{a}{a\sqrt{2}}\\=>\frac{1}{\sqrt{2}}$

(ii) Sec A

$Sec=\frac{Hypotenuse}{Adjacent}\\=>\frac{a\sqrt{2}}{a}\\=>\sqrt{2}$

(iii) $Cos^2\ A+Sin^2\ A\\Now, by\ identity\ cos^2\ A+sin^2\ A=1,\\we\ get\ the\ answer\ =1$

=1

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Answer 2

Good question..................