Question

calculate sodium chloride equivalent of drug having molecular weight 340 grams and lisa value is 0.25
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Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

The sodium chloride equivalent, E, measured is $0.0125 g^{-1}$.

Explanation:

Given,

The molecular weight of the drug = $340g$

The freezing point depression of an isotonic solution, $L_{iso}$ = $0.25$

The sodium chloride equivalent, E =?

As we know,

• The sodium chloride equivalent is used to measure the amount of sodium chloride required to prepare isotonic drug solutions.
• E = $\frac{17 L_{iso} }{M}$

Here,

• E = Sodium chloride equivalent
• $L_{iso}$ = Freezing point depression of an isotonic solution
• M = Molecular weight of the drug

After putting the given values in the equation, we get:

• E = $\frac{17\times 0.25}{340}$ = $0.0125 g^{-1}$

Hence, the sodium chloride equivalent, E = $0.0125 g^{-1}$.