Chemistry, asked by AdityaKannan, 1 year ago

Calculate solubility of Ca3(PO4)2 in pure water if its solubility product is 1.08×10^-23

Answers

Answered by Haziquemujtaba1
0
Ca3(PO4)2---------2Ca+ + 3PO4- y 2y 3y ksp={ (2y)^2. (3y)^3}/y =12y^4
Answered by kushalbaghat
0
5√ 0.1 × 10 ^ -23 .
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