Question

Calculate specific resistance of wire by using formula.​

Answer 1

Explanation:

ρ = RA/l

this is the formula

Answer 2

$</p><p>y = \sec( \sqrt{x} )y=sec( x)\\</p><p></p><p>Therfore\\</p><p></p><p>\begin{lgathered}\frac{dy}{dx} = \frac{d}{dx} ( \sec( \sqrt{x} ) \\ \frac{dy}{dx} = \sec( \sqrt{x}) \times \tan( \sqrt{x} ) \times \frac{d}{dx} ( \sqrt{x} ) \\ \frac{dy}{dx} = \sec( \sqrt{x} ) \tan( \sqrt{x} ) \times \frac{1}{2 \sqrt{x} } \\ \frac{dy}{dx} = \frac{ \sec( \sqrt{x} ) \tan( \sqrt{x} ) }{2 \sqrt{x} }\end{lgathered} </p><p>dx dy\\</p><p> </p><p> = </p><p>dx\\</p><p>d\\</p><p> </p><p> (sec( \\</p><p>x</p><p> \\</p><p> )</p><p>dx\\</p><p>dy\\</p><p> </p><p> =sec( </p><p>x</p><p> </p><p> )×tan( \\</p><p>x</p><p> </p><p> )× </p><p>dx</p><p>d</p><p> </p><p> ( </p><p>x\\</p><p> </p><p> )</p><p>dx</p><p>dy</p><p> </p><p> =sec( </p><p>x</p><p> </p><p> )tan( </p><p>x</p><p> </p><p> )× </p><p>2 </p><p>x</p><p> </p><p> </p><p>1</p><p> </p><p> </p><p>dx</p><p>dy</p><p> </p><p> = </p><p>2 </p><p>x</p><p> </p><p> </p><p>sec( </p><p>x</p><p> </p><p> )tan( </p><p>x</p><p> </p><p> )</p><p>$