Question

Calculate standard enthalpy of reaction.
2CH(g) + 702(g) + 4CO2(g) + 6 H20 (1)
Given: a) A,Hº (CO2)
-393.5 kJ/mol
b) 4,Hº :
= -84.9 kJ/mol
(H2O) = -285.8 kJ/mol
c) AfH0(c2h6) = -84.9​

Answer 1

Answer:

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