Question

Calculate standard enthalpy of reaction fe2o3+3co=2fe+3co2 from the following data.∆fh°(fe2o3)=-824kj/mol,∆fh°(co)=-110kj/mol,∆fh°(co2)=-393kj/mol​

Answer 1

Given:

∆fh° (fe2o3) = -824 kj/mol, ∆fh° (co) = -110 kj/mol, ∆fh° (co2) = -393 kj/mol​

To find:

Calculate standard enthalpy of reaction fe2o3+3co=2fe+3co2 from the following data.

Solution:

From given, we have,

∆fh° (fe2o3) = -824 kj/mol, ∆fh° (co) = -110 kj/mol, ∆fh° (co2) = -393 kj/mol​

we use the formula,

∆fh° = [2 ∆fh° (fe) + 3 ∆fh° (co2)] - [1 ∆fh° (fe2o3) + 3 ∆fh° (co)]

∆fh° = [2 (0) + 3 (-393)] - [1 (-824) + 3 (-110)]

∆fh° = [0 - 1179] - [-824 - 330]

∆fh° = - 1179 - [-1154]

∆fh° = - 1179 + 1154

∴ ∆fh° = - 25 kJ/mol

Therefore, the standard enthalpy of reaction fe2o3+3co=2fe+3co2  is - 25 kJ/mol

Answer 2

Answer:

your answer is in the above picture hope it was helpful