Calculate sum and average of the first 100 natural numbers using for
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sum=n÷2{2a+(n-1)×d}
=100÷2{2×1+(100-1)×1}
=50(2+99)
=50×101
=5050
or
n(n+1)÷2
100(100+1)÷2
10100÷2
= 5050
average=sum÷n
5050÷100
50.5
=100÷2{2×1+(100-1)×1}
=50(2+99)
=50×101
=5050
or
n(n+1)÷2
100(100+1)÷2
10100÷2
= 5050
average=sum÷n
5050÷100
50.5
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