Question

Calculate T1 and T2 for the following diagram

Answer 1

Explanation:

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Answer 2

Answer:

(1). $\frac{\sqrt{3}}{2}.mg$,  $T_{2}=\frac{mg}{2}$

Explanation:

In the given figure,

If we draw the free body diagram of the given mass hanging from the strings having tension T1 and T2 we can see,

So,

Because we can arrange the vectors of the Tension and the weight 'mg' vector we can simply form a triangle.

Therefore,

Using the Principle of Sine rule we can say that,

$\frac{T_{1}}{sin120}=\frac{T_{2}}{sin150}=\frac{mg}{sin90}$

Now,

On opening the give ratio we can simply find out that,

$\frac{T_{1}}{sin120}=\frac{mg}{sin90}=mg\\T_{1}=\frac{\sqrt{3}}{2}.mg$

And,

$\frac{T_{2}}{sin150}=\frac{mg}{sin90}=mg\\T_{2}=\frac{mg}{2}$

Therefore, the values of the Tension in the string is,

$T_{1}=\frac{\sqrt{3}}{2}.mg$ and $T_{2}=\frac{mg}{2}$

Hence, the correct option is (1).