Calculate
tan15/1-sec^215=
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than 45 and tha69 i think soooo
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tan15/1-sec215
tan45-tan30/1-sec215
tanA-tanB=tan(A+B)/1-tanAtanB
tan(1-1/√3/1-1/√3)1-sec(180+45)
tan(1)/1+sec45
tan1/1+√2=1/1+√2 ans
tan45-tan30/1-sec215
tanA-tanB=tan(A+B)/1-tanAtanB
tan(1-1/√3/1-1/√3)1-sec(180+45)
tan(1)/1+sec45
tan1/1+√2=1/1+√2 ans
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