Calculate temperature of 4 moles of gas occupying 5 do cube at 3.32 bar pressure (R=0.083 bar do cube k inverse mol inverse)
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If gas is assumed to be ideal then
Use ideal gas equation PV = nRT
T = PV / (nR)
= (3.32 bar × 5 dm³) / [4 mol × 0.083 bar dm³ / (mol^-1 K^-1)]
= 50 Kelvin
Temperature of gas is 50 Kelvin
Use ideal gas equation PV = nRT
T = PV / (nR)
= (3.32 bar × 5 dm³) / [4 mol × 0.083 bar dm³ / (mol^-1 K^-1)]
= 50 Kelvin
Temperature of gas is 50 Kelvin
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