Calculate. Temporary permanent and total hardness of water sample which has following impurities in mg/l. Ca(HCO3)2=48.6 mg/l, MgCl2=19mg/l, Mg SO4=60, Mg(NO3)2=29.6mg/l CaSO4=54.4 mg/l and Na2SO4=20mg/l.
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Answer:
Correct option is C)
mole of Ca(HCO
3
)
2
=
162g/mole
162×10
−3
mg
=1×10
−3
moles
Mole of Ca(SO
4
)=
136g/mole
136×10
−3
g
=1×10
3
mole
Total mole of Ca=2×10
−3
mole
mass of CaCO
3
=2×10
−3
×100=0.2g
∴ ppm (permanent hardness) =
1000
6.2
×10
6
=200ppm
Mole of MgCl
2
=
95
95×10
−3
=1×10
−3
mole
Mole Mg (HCg)
2
=
146
73×10
−3
=5×10
−4
mole
mole Mg =1.5×10
−4
mole
Mole g CaCO
3
(In terms of mg) =1.5×10
−3
mass =1.5×10
−3
=0.150g
ppm (temporary hardness) =
100
0.150
×106=150ppm
Hence, the correct option is C
Explanation:
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