Chemistry, asked by aniketthakur2228, 10 months ago

Calculate tge kinetic energy of 3 moles of carbondioxide at 27 degree

Answers

Answered by kingsleychellakkumar

0

Answer:

Kinetic energy = 3nRT/2

=3 x 3 x 8.314 x (273+27)/2

=9 x 8.314 x 300 / 2

=22447.8 / 2

= 11223.9 Joules.

Answered by AbdJr10

0

Answer:

11250 joule

Explanation:

hope the answer will help you

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