Question

Calculate tge kinetic energy of 3 moles of carbondioxide at 27 degree

Answer 1

Answer:

Kinetic energy  = 3nRT/2

                         =3 x 3 x 8.314 x (273+27)/2

                         =9 x 8.314 x 300 / 2

                         =22447.8 / 2

                         = 11223.9 Joules.

Answer 2

Answer:

11250 joule

Explanation:

hope the answer will help you