Question

calculate th number of atoms in 18.0 gm of glucose

Answer 1

★ Ello ★

here is your answer !!

given :- 18gm of glucose ( C6H12O6 )

mole = mass / molecular weight

=> C6H12O6

=> 12 × 6 + 12× 1 + 16 × 6

= 180 g

hence ,

mole = 18 / 180 g

1 / 10 × 6 .22 × 10 ²³

{ 6 .22 × 10 ²³ = avgadero number }

hence , total number of atom present in C6H12O6 ( glucose ) = 24 atoms

hence ,

Total number of atom present in C6H12O6 is

1 / 10 × 6.22 × 10 ²³ × 24 atom

hope it helps you dear !!

thanks !!

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