Chemistry, asked by betsybbt, 5 months ago

calculate th pH of a solution of KOH made by dissolving 0.56g in one liter

Answers

Answered by princeuplucky123449

0

Answer:

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Explanation:

Molarity of KOH solution = =

Molecular weight×volume

Weight

=

56×1

5.6

=0.1 M.

This is equal to [OH

−

].

pOH=−log[OH

−

]=−log(0.1)=1

pH=14−pOH=14−1=13.

Hence, option B is correct.

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