Calculate thd columb force between 2 alpha partical sperated by a distance of 3.2 ×10^-15
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Coloumb force
F= kq1q2/r2
As q1=q2=1.6 * 10-19 (for alpha particles)
R=3.2 * 10-15
And K=9 * 109
Therefore, F= (9 * 109) * (1.6 * 10-19) * (1.6 * 10-19)/ (3.2 * 10-15)2
F= (23.04 * 10-29)/(10.24 * 10-30)
F=2.25 * 10
F=22.5 N
F= kq1q2/r2
As q1=q2=1.6 * 10-19 (for alpha particles)
R=3.2 * 10-15
And K=9 * 109
Therefore, F= (9 * 109) * (1.6 * 10-19) * (1.6 * 10-19)/ (3.2 * 10-15)2
F= (23.04 * 10-29)/(10.24 * 10-30)
F=2.25 * 10
F=22.5 N
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