Question

Calculate the 4 Hº at 298 K for the reaction :
C (graphite) + 2H2(g) → CH2(g)
from the following data :
C (graphite) + O2(g) CO2(g)
4,Hº = - 393.5 kJ mol-1
H2(g) +
+0,8) → H,O(1)
4 Hº = -285.8 kJ mol-
CO2(g) + 2H,0(1) - CH2(g) + 20,8 )
4H° = + 890.3 kJ mol-1​

Answer 1

Answer:

Explanation:

you are given 75 g of O2,, how many grams of CO2 are made? Show your work :)