Question

Calculate the a) Molecular mass and molar of H2SO4 (H- 1u, S- 32u, O-16u) b) No of moles in 51g of Ammonia (N- 14u, H-1) c) Mass of 1.5 moles of CH4

Answer 1

Explanation:

(i) H2SO4 = H x 2 + S x 1 + O x 4

= 2 + 32 + 64

= 98 u

Molar mass = 98 g

(ii) NH3 - Ammonia( molar mass ) = N x 1 + H x 3

= 14 + 3

= 17g

No. of moles = Given mass/Molar mass

= 51/17

=3 moles

(iii) Given no. of moles = 1.5 or 3/2 moles

Molar mass of CH4 = C x 1 + H x 4

= 12 + 4

= 16 g

No. of moles = Given mass / Molar mass

3/2 = x / 16

3/2 x 16 = x

x = 3 x 8

x = 24 g

Pls mark me as brainliest

Thank you