calculate the
a) No of mol
b) No of molecules
c) No of atoms
d) mass of H2SO4
✴ PRESENT IN 21 GRAM ATOM OF H2SO4.
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ANSWERS :-
1 mole of H2SO4 = 6.022 * 10²³ molecules = 98 gram = 1gram–atom
= 7 * 6.023 *10²³atoms = 7 gram atom
we calculate first of all atom ,
7 gram – atom contain = 7*6.023*10²³ atom
1 gram – atom contain = 7*6.023*10²³/7 atom
21 gram – atom contain = 7*6.023*10²³*21/7 atom
question c ) answer = 21 * 6.023 *10²³ atom
Now ,
we calculate no of mole = 21 * 6.023 * 10²³/7 * 6.023 *10²³
question A answer = 3 mole
Now ,
question B answer =
No of molecules = 3 * 6.023 * 10²³
Now,
QUESTION D ANSWER
mass of H2SO4 = 98 * 3
= 294 gram
_____________________________
❤BE BRAINLY ❤
________________
1 mole of H2SO4 = 6.022 * 10²³ molecules = 98 gram = 1gram–atom
= 7 * 6.023 *10²³atoms = 7 gram atom
we calculate first of all atom ,
7 gram – atom contain = 7*6.023*10²³ atom
1 gram – atom contain = 7*6.023*10²³/7 atom
21 gram – atom contain = 7*6.023*10²³*21/7 atom
question c ) answer = 21 * 6.023 *10²³ atom
Now ,
we calculate no of mole = 21 * 6.023 * 10²³/7 * 6.023 *10²³
question A answer = 3 mole
Now ,
question B answer =
No of molecules = 3 * 6.023 * 10²³
Now,
QUESTION D ANSWER
mass of H2SO4 = 98 * 3
= 294 gram
_____________________________
❤BE BRAINLY ❤
________________
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