Question

Calculate the accelaration and distance of the body moving with 5m/s which comes to rest after traveling for 6 sec?

Answer 1

Answer:

0.83333..m2/s

Explanation:

given- v= 5m/s

u=0m/s(as the body starts from rest)

t=6s

as we know that acceleration (a)=v-u/t

so,a=5-0/6

a=5/6m2/s

or 0.8333m2/s