Question

calculate the acceleratetion produce when a car running in the velocity of 20m/s changes its velocity of 45m/sin 6s solve this numerical problem​

Answer 1

Given:-

• Initial velocity ,u = 20m/s
• Final velocity ,v = 45m/s
• Time taken ,t = 6s

To Find:-

• Acceleration ,a

Solution:-

According to the Question

We have to calculate the acceleration of the car.

As we know that acceleration is defined as the rate of change in velocity.

• a = v-u/t

where,

• v is the final velocity
• a is the acceleration
• u is the initial velocity
• t is the time taken

substitute the value we get

$:\implies$ a = 45-20/6

$:\implies$ a = 25/6

$:\implies$ a = 4.16 m/s²

• Hence, the acceleration of the car is 4.16 m/s².

Answer 2

Answer:

Given :-

• A car running in the velocity of 20 m/s changes its velocity of 45 m/s in 6 seconds.

To Find :-

• What is the acceleration of a car.

Formula Used :-

$\clubsuit$ First equation of motion :

$\longmapsto \sf\boxed{\bold{\pink{v = u + at}}}$

where,

• v = Final Velocity
• u = Initial Velocity
• a = Acceleration
• t = Time

Solution :-

Given :

• Final Velocity = 45 m/s
• Initial Velocity = 20 m/s
• Time = 6 seconds

According to the question by using the formula we get,

$\longrightarrow \sf 45 =\: 20 + a(6)$

$\longrightarrow \sf 45 =\: 20 + 6a$

$\longrightarrow \sf 45 - 20 =\: 6a$

$\longrightarrow \sf 25 =\: 6a$

$\longrightarrow \sf \dfrac{25}{6} =\: a$

$\longrightarrow \sf 4.16 =\: a$

$\longrightarrow \sf\bold{\red{a =\: 4.16\: m/s^2}}$

$\therefore$ The acceleration of a car is 4.16 m/s².