Question

calculate the acceleration a car that has covered 50 m at a velocity of 2m/s after its brakes were applied to make it stop.a=_m/s^2​

Answer 1

Given :-

• Distance covered (s) = 50m
• Initial velocity (u) = 2m/s
• Final velocity (v) = 0 {brakes are applied}

To find :-

• Calculate acceleration

Solution :-

According to the third equation of motion

➭ v² = u² + 2as

➭ (0)² = (2)² + 2*a*50

➭ 0 = 4 + 100a

➭ - 4 = 100a

➭ a = -4/100

➭ a = -0.04m/s²

Minus shows retardation

Hence,

• Acceleration of a car is - 0.04m/s²

Answer 2

☆ Given :-

• Distance Covered = 50m.

• Final Velocity = 2m/s

• Initial Velocity = 0m/s

☆ To Find :-

• Acceleration Of Car

☆ Solution :-

Using Third Equation Of Kinematics,

v² = u² + 2as.

➝ 0² = 2² + 2×50a.

➝ 0 = 4 + 100a.

➝ 100a = -4.

➝ a = -0.04m/s²

Hence, Retardation = -0.04m/s².