Question

Calculate the acceleration and distance of the body moving with 5m/s2 which comes to rest after travelling for 6s

Answer 1

u=5m/s^2

v=0

t=6 sec

v=u+at=0=5+6a

therefore a=-5/6m/s^2

s=ut+1/2at^2

s=30+1/2×-5/6×36

=15m.

this is correct solution.