Calculate the acceleration and distance of the body moving with 5m/s^2 which comes to rest after travelling for 6sec?
Answers
Answered by
0
Answer:
U=5m/s
v=0
t=6s
a=v-u/t
a=-5/6m/s²
Explanation:
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Answered by
2
Answer:
v=u+at
a=v-u/t
a=0-5/6
= - 5/6m/s^2
v^2-u^2=2as
0-25=2*-5/6*s
25=10/6s
s=150/10=15m
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