Physics, asked by nishikarana121, 10 months ago

Calculate the acceleration and distance of the body moving with 5m/s^2 which comes to rest after travelling for 6sec?

Answers

Answered by MʏSᴛᴇʀɪᴏSᴛᴀʀᴋ
0

Answer:

U=5m/s

v=0

t=6s

a=v-u/t

a=-5/6m/s²

Explanation:

please mark me brainliest and follow me

Answered by aarvikoberoi2
2

Answer:

v=u+at

a=v-u/t

a=0-5/6

= - 5/6m/s^2

v^2-u^2=2as

0-25=2*-5/6*s

25=10/6s

s=150/10=15m

Similar questions