Calculate the acceleration and distance of the body moving with 5 m / s which comes to rest after travelling 6 sec
Answers
Answered by
1
Explanation:
v=u+at
0=5+6a
a=-5/6
s=ut+1/2at²
s=5*6+1*-5*6*6/2*6
30-15=15 metre
Answered by
0
Answer
u = 5m/s
t = 5 s
a = 5m/s²
by second equation of motion
s = ut + 1/2 at²
= 5 × 5 + 1/2 (5) × 5²
= 25 + 62.5
= 87.5 m
Distance travel by object moving with m/s in 5 s when acceleration is 5m/s² is 87.5 m.
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