Question

Calculate the acceleration and distance of the body moving with 5 m / s which comes to rest after travelling 6 sec
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Answer 1

Explanation:

v=u+at

0=5+6a

a=-5/6

s=ut+1/2at²

s=5*6+1*-5*6*6/2*6

30-15=15 metre

Answer 2

Answer

u = 5m/s

t = 5 s

a = 5m/s²

by second equation of motion

s = ut + 1/2 at²

= 5 × 5 + 1/2 (5) × 5²

= 25 + 62.5

= 87.5 m

Distance travel by object moving with m/s in 5 s when acceleration is 5m/s² is 87.5 m.