Question

Calculate the acceleration and distance of the body moving with 5m/s² which comes to rest after traveling for 6sec?

Answer 1

u=5m/s

v=0

t=6sec

a=?

s=?

v=u+at

0=5+6a

a=-5/6

here a is negative because of retardation

s=ut+1/2 at^2

=30+1/2×6×6×(-5/6)

=30-15

=15m

Answer 2

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