Calculate the acceleration due to gravity at a height of 300 km from the surface of the Earth. (M=5.98x10^24 kg, R= 6400 km).
[Ans :-8.889 m/s²]
Answers
Answered by
19
Explanation:
Dear Student,
◆ Answer -
Gravitational acceleration at 300 km = 9.36 m/s²
● Explanation -
Acceleration due to gravity at height h is given by -
g' = gR²/(R+h)²
Substitute values,
g' = 9.8 × 6.4×10^6 / (6.4×10^6 + 0.3×10^6)
g' = 9.36 m/s²
Therefore, acceleration due to gravity at a height of 300km from the surface of the surface of the earth is 9.36 m/s².
Answered by
9
Answer:
8.889
Explanation
given; m=5.98
R=6400km=6400000m
h=300km=300000m
gh=GM/(R+h)^2
=6.67*10^-11 *5.98*10^24 / ( (6400+300)10^3 )^2
6.67*5.98*10^13/(6700)^2*10^6
6.67*5.98*10^13/6.7^2*10^13
6.67*5.98/6.7^2
8.889
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