Question

Calculate the acceleration due to gravity at a height of 300 km from the surface of the Earth. (M=5.98x10^24 kg, R= 6400 km).
[Ans :-8.889 m/s²]​

Answer 1

Explanation:

Dear Student,

◆ Answer -

Gravitational acceleration at 300 km = 9.36 m/s²

● Explanation -

Acceleration due to gravity at height h is given by -

g' = gR²/(R+h)²

Substitute values,

g' = 9.8 × 6.4×10^6 / (6.4×10^6 + 0.3×10^6)

g' = 9.36 m/s²

Therefore, acceleration due to gravity at a height of 300km from the surface of the surface of the earth is 9.36 m/s².

Answer 2

Answer:

8.889

Explanation

given; m=5.98    

          R=6400km=6400000m

          h=300km=300000m

gh=GM/(R+h)^2

   =6.67*10^-11 *5.98*10^24 / ( (6400+300)10^3 )^2

   6.67*5.98*10^13/(6700)^2*10^6

   6.67*5.98*10^13/6.7^2*10^13

  6.67*5.98/6.7^2

  8.889