Question

calculate the acceleration due to gravity at the top of a mountain of height 8km from the surface of the earth. the mass of the earth is 6×10^24kg and its radius is 6.4×10^3km​

Answer 1

Answer:

Explanation:

Given,

h=8848m

The value of sea level is 9.08m/s  

2

 

So,

Let g  

′

 be the acceleration due to the gravity on the Mount Everest.

g  

′

=g(1−  

h

2h

​

)

=9.8(1−  

6400000

17696

​

)

=9.8(1−0.00276)

9.8×0.99724

=9.773m/s  

2

 

Thus, the acceleration due to gravity on the top of Mount Everest is =9.773m/s  

2