calculate the acceleration due to gravity on a planet whose mass is double and the radius is three times that of the earth take g= 10ms-2
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We know,
g = GM/R²
Given, M’ = 2m
R = 3r
Putting the values, we get :
g’ = G × 2m/(3r)² = Gm/r² × 2/9 = 2g/9 = 2×9.8 /9 = 2 × 1.1 = 2.2m/s²
Explanation:
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