Question

Calculate the acceleration due to gravity on a spaceship ata distance equal to twice the Earth’s radius from the centre of the Earth.(g = 9.8 m s-2

Answer 1

Answer :

We have asked to find acceleration due to gravity at a distance equal to twice the earth's radius from the centre of the earth$.$

★ The acceleration due to gravity decreases both with the increase in height and increase in depth. So it is maximum at the surface of the earth and zero at the centre of the earth.

Acceleration due to gravity at height from the surface of earth is given by

• g' = g / (1 + h/R)²

R denotes radius of earth

g denotes acceleration due to gravity at surface of the earth

Here height of spaceship from the surface of earth will be R.

➠ g' = g / (1 + h/R)²

➠ g' = 9.8 / (1 + R/R)²

➠ g' = 9.8/(2)²

➠ g' = 9.8/4

➠ g' = 2.45 m/s²