Question

Calculate the acceleration due to gravity on the surface of a satellite having a mass of 7.4×10^22kg and radius of 1.74×10^6 m (G=6.7×10^-11Nm^2Kg^2)

Answer 1

Hello Mate!

Hence, g = GM / R²

Here, value of G = 6.67 ^ -11

M = 7.4 × 10²² kg and R = 1.74 × 10^6 m

g = ( 6.7 × 10^-11 × 7.4 × 10²² )/( 1.74 × 10^6 )²

= ( 49.58 × 10¹¹ )/( 3.0276 × 10¹² )

= 16.4 × 1 / 10

=> 1.64 m/s²

Have great future ahead!

Answer 2

here is your solution OK ⛲⛲⛲⛲⛲⛲⛲

$\huge \large {thanks \: }$
Mass of moon is, M = 7.31 × 1022 kg

Radius of moon is, R = 1.7 × 106 m

So, acceleration due to gravity of moon is, gm = GM/R2

=> gm = (6.67 × 10-11)(7.31 × 1022)/(1.7 × 106)2

=> gm = 1.68 m/s2