Question

Calculate the acceleration of a body initially moving with velocity 20 m/s whose velocity changes to 30 m/s in 10 minutes

Answer 1

Given:

Initial velocity of body, u= 20 m/s

Final velocity of body, v= 30 m/s

Time taken by body, t= 10 min= 600 s

To Find:

Acceleration of body

Solution:

We know that,

• According to first equation of motion for constant acceleration

$\pink{\boxed{\bf{v=u+at}}}$

where,

v is final velocity

u is initial velocity

a is acceleration

t is time taken

$\rule{190}{1}$

Let the acceleration of given body be 'a'

So, on applying first equation of motion on given body, we get

$\longrightarrow\rm{v=u+at}$

$\longrightarrow\rm{30=20+a(600)}$

$\longrightarrow\rm{30-20=a(600)}$

$\longrightarrow\rm{10=600a}$

$\longrightarrow\rm{600a=10}$

$\longrightarrow\rm{a=\dfrac{\cancel{10}}{\cancel{600}}}$

$\longrightarrow\rm{a=\dfrac{1}{60}}$

$\longrightarrow\rm\green{a=0.0166\:m/s^{2}}$

Hence, acceleration of given body is 0.0166 m/s².

Answer 2

Answer:

Explanation:

Given :-

Initial velocity of body, u = 20 m/s

Final velocity of body, v = 30 m/s

Time taken by body, t = 10 min = 10 × 60 = 600 seconds

As 1 min = 60 seconds

To Find :-

Acceleration of body, a = ??

Formula to be used :-

1st equation of motion

i.e v = u + at

Solution :-

Putting all the values, we get

v = u + at

⇒ 30 = 20 + a × 600

⇒ 30 = 20 + 600a

⇒ 30 - 20 = 600a

⇒ 10 = 600a

⇒ 10/600 = a

⇒ a = 0.0166 m/s²

Hence, the acceleration of a body is 0.0166 m/s².