calculate the acceleration of a body which starts from rest and travel a distance of 87.5 m 5 second
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Answered by
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Explanation:
using the equation of motion
initial velocity is 0 as body starts from rest
S=u*t+1)2a*(t^2)
where u=initial velocity, s=displacement, t=time, a= accelaration of the body
u=0 s=87.5m t=5 sec
putting in the equation
87.5*2/(5^2)=a
a=7m/s^2
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Answered by
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S = ut +1/2at²
A= 7m / s²
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