Question

calculate the acceleration of a body which starts from rest and travel 87.5m in 5sec​

Answer 1

Answer:

given

the body started from rest

so u=0

s=87.5m

t=5sec

a=?

s=ut+1/2at^2(equation of motion)

87.5=0×5+1/2(25a)

87.5×2=25a

175=25a

175/25=a

a=7

Answer 2

$\huge{\longrightarrow{\rm{ANSWER}}}{\leftarrow}$

Given :-

A body which starts from rest and travels 87.5 meters in 5 seconds

Required to find :-

• Acceleration of the body ?

Concept used :-

• Equations of motion

Equation used :-

$\huge{\dagger{\boxed{\tt{ s = ut + \dfrac{1}{2}at^2 }}}}{\bigstar}$

Solution :-

Given that :-

A body which starts from rest and travels 87.5 meters in 5 seconds

we need to find the acceleration of the body

So,

Consider the statement which is given that is ,

A body which starts from rest and travels 87.5 meters in 5 seconds

From the above we can conclude that ,

initial velocity of the body ( u ) = 0 m/s

Displacement ( s ) = 87.5 meters

Time taken ( t ) = 5 seconds

By using the 2nd equation of motion

$\huge{\dagger{\boxed{\tt{ s = ut + \dfrac{1}{2}at^2 }}}}{\bigstar}$

here,

s = displacement

u = initial velocity

t = time taken

a = acceleration

So,

Substitute the given values in the equation

$\longrightarrow{\mathsf{ 87.5 = 0 \times 5 + \dfrac{1}{2} \times a \times {5}^{2}}}$

$\longrightarrow{\mathsf{ 87.5 = 0 + \dfrac{ 1 }{2} \times a \times 5 \times 5 }}$

$\longrightarrow{\mathsf{ 87.5 = 0 + \dfrac{ 1 }{2} \times a \times 25 }}$

By transposing 2 to the right side

$\longrightarrow{\mathsf{ 87.5 \times 2 = 25a }}$

transpose 25 to the left side

$\longrightarrow{\mathsf{ \dfrac{87.5 \times 2}{25} = a }}$

interchanging the terms on both sides

$\longrightarrow{\mathsf{ a = \dfrac{87.5 \times 2 }{25}}}$

$\longrightarrow{\mathsf{ a = \dfrac{ 17.5 \times 2}{5} }}$

$\longrightarrow{\mathsf{ a = \dfrac{35}{5}}}$

$\longrightarrow{\mathsf{ a = 7 \; m/{s}^{2} }}$

So,

$\huge{\therefore{\tt{Acceleration = 7 \; m/s^2 }}}$

Points to remember :-

3 equations of motion are ;

1. v = u + at

2. s = ut + ½ at²

3. v² - u² = 2as

Here,

v = final velocity

u = initial velocity

s = displacement

a = acceleration

t = time taken