Question

Calculate the acceleration of a body which starts from rest and travels 87.5m 5sec

Answer 1

Given:

The Displacement is,

s = 87.5 m

The time is,

t = 5 sec

The initial velocity is,

u = 0 m/sec

To find:

Acceleration (a) = ?

Solution:

As we know,

⇒ $s = ut+\frac{1}{2}at^2$

By substituting the values, we get

$87.5=0\times 5+\frac{1}{2}\times a\times (5)^2$

$87.5=\frac{1}{2}\times a\times 25$

     $a = \frac{87.5}{12.5}$

        $=7 \ m/s^2$

Thus the acceleration will be "$7 \ m/s^2$".

Answer 2

Answer: The acceleration will be 7 m/s².

Explanation:

According to the question,

As the given displacement is 87.5 m

And the time is 5sec.

Where the initial velocity is u=0m/sec

As we have to find the acceleration (a)=?

As we know, s = ut + $\frac{1}{2} at^{2}$

So now by substituting the values,

87.5 = 0×5+$\frac{1}{2}a\times 5^{2}$

87.5 = $\frac{1}{2} \times a \times 25$

    a = $\frac{87.5}{12.5}$

    a = 7 m/s²

Hence, the acceleration will be 7 m/s².

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