Question

Calculate the acceleration of a car moving at 15 m/s which comes to a stop in 3 s.

Answer 1

Answer:

Correct option is

D

225 m

Initial velocity or speed u=15m/s

The acceleration a=−0.5m/s

2

When vehicle stops its final velocity becomes zero v=0

By applying equation of motion

v

2

=u

2

+2aS

0=225−2×0.5S

S=

2×0.5

225

=225m

Explanation:

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Answer 2

Explanation:

here , velocity is 15 m/s

and,. time is 3s

We know that a= v/ t

so,. a = 15 /3

hence ,. a= 5 m/ s2