Calculate the acceleration of a particle at t=π/6, if the position of the particle is given by,
x= 6t^2sin2t
(Here x is in meters,t is in seconds, please help)
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⭐Actually Welcome to the Concept of the kinematics
⭐We use here the Product rule to differentiate the function w. r. t time
⭐that is
⭐d(u.v) /dt = v. du/dt + u. dv/dt
⭐so after solving we get as
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