Question

Calculate the acceleration of Josh riding his bicycle in a straight line that spread up 4 metre per second to 6 metre per second in 5 second

Answer 1

GIVEN :-

• Initial velocity(u) of Josh = 4 m/s

• Final velocity(v) of Josh = 6 m/s

TO FIND :-

The acceleration of Josh.

FORMULA TO BE USED :-

$\sf{v = u + at}$

$\sf{Or,}\ \sf{a=\dfrac{v-u}{t}}$

If 'u' is the initial velocity of an object, 'v' is the final velocity attained by the object after 't' seconds of time, then acceleration 'a' is given by:

a = Change in velocity/Time taken

⇒ a = (Final velocity - Initial velocity)/Time taken. a = (v-u)/t. at = (v-u)

SOLUTION :-

Putting the known values in the above equation :-

$\sf{a=\dfrac{6-4}{5}}\\\\\sf{\longrightarrow a=\dfrac{2}{5} }\\\\\boxed{\underline{\boxed{\sf{\longrightarrow a=0.4\ m/s^2}}}}$

Therefore, the acceleration of Josh is 0.4 m/s².

Answer 2

Answer:

0.4 m/s²

Explanation:

Given :

Initial velocity = u = 4 m/s

Final velocity = v = 6 m/s

Time = t = 5 seconds

To find :

Acceleration of the bicycle

Acceleration = (final velocity - Initial velocity)/time

Substituting the above values,

Acceleration = ( 6-4 ) /5

Acceleration = 2/5

Acceleration = 0.4 m/s²

The bicycle will move with an acceleration of 0.4 m/s² which will gradually increase the speed of the bicycle with time