Physics, asked by janvi1685, 10 months ago

calculate the acceleration of the body which was moving with the velocity of 40m/sec and was stopped by applying breaks, also calculate the distance travelled by it in 5 sec​

Answers

Answered by Anonymous
8

Given:

  • Initial velocity,u = 40 m/s

  • Final velocity,v = 0 m/s

  • Time taken,t = 5 s

To be calculated:

Calculate the acceleration and distance travelled of the body.

Formula used:

  • v = u + at

  • s = ut + 1/2at²

Solution:

Case 1 :

From first equation of motion

v = u + at

★ Substituting the values in the above formula,we get

⇒ 0 = 40 + a × 5

⇒ 0 = 40 + 5a

⇒ 5a = -40

⇒ a = -40/5

⇒ a = -8 m/s² [ negative acceleration ]

Thus,the acceleration of given body is -8 m/s².

Case 2:

From Second equation of motion

s = ut + 1/2 at²

s = 40 × 5 + 1/2 × -8 × ( 5 )²

s = 200 + ( -4 ) × 25

s = 200 - 100

s = 100 m

Thus,the distance covered by given body is 100 metres.

Answered by sethrollins13
67

✯✯ QUESTION ✯✯

Calculate the acceleration of the body which was moving with the velocity of 40m/sec and was stopped by applying breaks, also Calculate the distance travelled by it in 5 sec ..

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✰✰ ANSWER ✰✰

\implies\tt{Initial\:Velocity(u)=40m/s}

\implies\tt{Final\:Velocity(v)=0m/s}

\implies\tt{Time\:Taken(t)=5\:sec.}

Firstly , We will Find the Acceleration ..

Using 1st Equation Of Motion : -

\implies\tt{\small{\boxed{\bold{\bold{\red{\sf{v=u+at}}}}}}}

Putting Values : -

\implies\tt{0=40+a(5)}

\implies\tt{0=40+5a}

\implies\tt{-40=5a}

\implies\tt{a=\cancel\dfrac{-40}{5}}

\red\longmapsto\:\large\underline{\boxed{\bf\green{a}\orange{=}\purple{-8}}}

Acceleration of the Body is -8m/s ..

Now ,

We will find the distance travelled by the body ..

Using 2nd Equation of Motion : -

\implies\tt{\small{\boxed{\bold{\bold{\blue{\sf{s=ut+\dfrac{1}{2}{at}^{2}}}}}}}}

Putting Values : -

\implies\tt{s=40(5)+\dfrac{1}{2}\times{-8}\times{{(5)}^{2}}}

\implies\tt{s=200+\dfrac{1}{\cancel{2}}\times{\cancel{-8}}\times{25}}

\implies\tt{s=200-100}

\green\longmapsto\:\large\underline{\boxed{\bf\pink{s}\orange{=}\blue{100}}}

So , The distance travelled by the body is 100m.

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