Calculate the acceleration of the car for each set of conditions using the formula
a = (v2 – v1) / (t2 – t1)
where v2 and v1 are the first and second velocities and t1 and t2 are the average times the car took to reach the 0.25 and the 0.50 meter marks. Acceleration is reported in m/s2. Record these accelerations, to two decimal places, in Table E.
The acceleration for the car with one washer is
m/s2.
The acceleration for the car with two washers is
m/s2.
The acceleration for the car with three washers is
m/s2.
The acceleration for the car with four washers is
m/s2.
Answers
Answered by
2
Answer:
Explanation:
Time passed before the speed change
speed = d1/t1 ;
65 mi/h = (130 mi)/t1
t1 = 2.0 h.
the time at the lower speed is
t2 = T — t1 = 3.33 h — 2.0 h = 1.33 h.
We discover the separation went at the lower speed from
speed = d2/t2;
55 mi/h = d2/ (1.33 h), which gives d2 = 73 mi.
The complete separation =
D = d1 + d2 = 130 mi + 73 mi = 203 mi.
normal speed = d/t = (203 mi)/(3.33 h) = 61 mi/h.
Note that the normal speed isn’t!
(65 mi/h + 55 mi/h). The two rates were not kept up for
break even with times
Answered by
1
Answer:
0.33
Explanation:
if its on edge and there are no answer choices then im right.
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