Question

calculate the acceleration of the car if the force of 5N is applied after 2 minutes , its velocity increases to 6 m/s​

Answer 1

Explanation:

given:-

f= 5N

t= 2m= 120s

v= 6m/s

u=0

a=(v-u)/t

a= (6-0)/120

a= 1/20m/s2

Answer 2

Answer:

given:

given:f=5N

given:f=5Nt=2m= 120s

given:f=5Nt=2m= 120sv=6m/s

given:f=5Nt=2m= 120sv=6m/su=0

given:f=5Nt=2m= 120sv=6m/su=080D)

given:f=5Nt=2m= 120sv=6m/su=080D)a=(v-u)/t

given:f=5Nt=2m= 120sv=6m/su=080D)a=(v-u)/ta= (6-0)/120

given:f=5Nt=2m= 120sv=6m/su=080D)a=(v-u)/ta= (6-0)/120a=1/20m/s2