Question

Calculate the acceleration of the car moving with a velocity of 2 m/s changed in to 12 m/s in 5 seconds.​

Answer 1

Explanation:

Velocity is vector quantity so direction matters.

v

i

=25m/s,v

f

=−25m/s.

Δv=(−25)−25=−50m/s

Average acceleration =

Δt

Δv

=

5

50

=10ms

−2

.

Answer 2

Answer:

2

Explanation:

$a = \frac{v - u}{t} \\ = \frac{12 - 2}{5} \\ = \frac{10}{5} \\ = 2m {s}^{ - 2}$

Hope this helps ;)