Question

Calculate the acceleration of the car starting from rest which attains a velocity of 30 m/s in 3 minutes

Answer 1

Given:

Initial velocity (u) = 0 m/s

Final velocity (v) = 30 m/s

Time taken (t) = 3 min = 180 s

To Find:

Acceleration (a)

Answer:

From first equation of motion:

$\bf \leadsto v = u + at \\ \\ \rm \leadsto 30 = 0 + 180t \\ \\ \rm \leadsto t = \dfrac{3 \cancel{0}}{18 \cancel{0}} \\ \\ \rm \leadsto t = \dfrac{1}{6} \: s \\ \\ \rm \leadsto t = 1.67 \: s$

$\therefore$ Acceleration (a) of the car = 1.67 s

Answer 2

Answer:

• The acceleration of the car is 1.67 ms-².

Explanation:

Given that,

• Initial velocity (u) = 0 ms-¹
• Final velocity (v) = 30 ms-¹
• Time (t) = 3 min = 180 s

Applying 1st eqn. of motion,

$\purple\bigstar$ v = u + at

[ Putting values ]

↪ 30 = 0 + a × 180

↪ 30 = 180a

↪ a = 30/180

↪ a = 1.67 ms-² $\red\bigstar$

For information:

• s = ut + 1/2 at²
• v² = u² + 2as