Question

calculate the acceleration of the car starting from rest which attain a velocity of 30m/s in 180s​

Answer 1

Provided that:

• Initial velocity = 0 mps
• Final velocity = 30 mps
• Time = 180 seconds

Don't be confused! Initial velocity cames as zero because the car starts from rest.

To calculate:

• The acceleration

Solution:

• The acceleration = 0.16 mps sq.

Using concept:

• Acceleration formula

Using formula:

• ${\small{\underline{\boxed{\pmb{\sf{a \: = \dfrac{v-u}{t}}}}}}}$

Where, a denotes acceleration, u denotes initial velocity, v denotes final velocity and t denotes time taken.

Some procedure: To solve this question we have to use acceleration formula and put the values according to the formula to get the required solution. Let's see how to solve this question!

$:\implies \sf a \: = \dfrac{dv}{dt} \\ \\ :\implies \sf a \: = \dfrac{\Delta \: v}{t} \\ \\ :\implies \sf Acceleration \: = \dfrac{Change \: in \: velocity}{Time} \\ \\ :\implies \sf Acceleration \: = \dfrac{v-u}{t} \\ \\ :\implies \sf Acceleration \: = \dfrac{30-0}{180} \\ \\ :\implies \sf Acceleration \: = \dfrac{30}{180} \\ \\ :\implies \sf Acceleration \: = \dfrac{3\not{0}}{18\not{0}} \\ \\ :\implies \sf Acceleration \: = \dfrac{3}{18} \\ \\ :\implies \sf Acceleration \: = \dfrac{1}{6} \: ms^{-2} \\ \\ :\implies \sf Acceleration \: = 0.16 \: ms^{-2}$

About acceleration:

$\begin{gathered}\boxed{\begin{array}{c}\\ \bf What \: is \: acceleration? \\ \\ \sf The \: rate \: of \: change \: of \: velocity \: of \: an \\ \sf object \: with \: respect \: to \: time \\ \sf is \: known \: as \: acceleration. \\ \\ \sf \star \: Negative \: acceleration is \: known \: as \: Deceleration. \\ \sf \star \: Deceleration \: is \: known \: as \: retardation. \\ \sf \star \: It's \: SI \: unit \: is \: ms^{-2} \: or \: m/s^2 \\ \sf \star \: It \: may \: be \: \pm ve \: or \: 0 \: too \\ \sf \star \: It \: is \: a \: vector \: quantity \\ \\ \bf Conditions \: of \pm ve \: or \: 0 \: acceleration \\ \\ \sf (1) \: Positive \: acceleration: \: \sf When \: \bf{u} \: \sf is \: lower \: than \: \bf{v} \\ \sf (2) \: Negative \: acceleration: \: \sf When \: \bf{v} \: \sf is \: lower \: than \: \bf{u} \\ \sf (3) \: Zero \: acceleration: \: \sf When \: \bf{v} \: \sf and \: \bf{u} \: \sf are \: equal \end{array}}\end{gathered}$

Answer 2

QUESTI0N:-

Calculate the acceleration of the car starting from rest which attain a velocity of 30m/s in 180s​

EXPLANATION:-

We know that:-

a=(v-u)/t

Where :-

a=acceleration

v=final velocity

u=initial velocity

t=time taken

In this question:-

• acceleration=?
• Final velocity=30 m/s
• Initial velocity=0 m/s
• Time=180 s

Let's find acceleration:-

a=(30-0)/180

a=30/180

a=3/18

a=1/6 m/s²

So the acceleration is 1/6 m/s²

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