Question

calculate the acceleration of the car that has covered 50 m at a velocity of 2 m/s after its brakes were applied to make the car stop
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Answer 1

Answer:

here ,

u= 2 m/s

distance = 50 m

v = 0 m/s

∴ t = distance / speed = 50 / 2 = 45 sec

now , a = v - u / t  

      = 0 - 2 / 45

     = - 0.04 m/s²

this was the first method, we can do it by another method also,

by taking the equation , v ² - u² = 2 as,

v = 0 , u = 2 and s = 50

=> 0² - 2² = 2×a×50

=> - 4 = 100 a

=> -a =4/100

=> a = - 0.04 m/s²

here - sign means the object is in a retardation .

hope you understand ,  this is the correct answer for your question. plz mark it brainliest.

Answer 2

GIVEN:-

• $\rm{Initial\:Velocity = 2m/s^{-1}}$

• $\rm{Final\:Velocity= 0m/s^{-1}}$(as the brakes were applied).

• $\rm{Distance\: Covered = 50m}$

TO FIND:-

• Acceleration ? or retardation?

FORMULAE USED:-

• ${\huge{\boxed{\rm{v^2 - u^2 = 2as}}}}$

Where,

v = Final Velocity

u = Initial Velocity

a = Acceleration

S = Distance Covered

Now,

$\implies\rm{ v^2 - u^2 = 2as}$

$\implies\rm{ (0)^2 - (2)^2 = 2\times{a}\times{50}}$

$\implies\rm{ -4 = 100a}$

$\implies\rm{ a = \dfrac{-4}{100}}$

$\implies\rm{ a = -0.04m/s^{-2}}$.

Hence, The retardation is -0.04m/s²

EXPLORE MORE!!!

• The shortest distance between initial and final position is called Displacement.

• Displacement can be zero if the object moves in straight line.

• Distance is the actual path travelled by body, it can never be zero.

• Displacement is vector quantity while Distance is Scalar quantity.

• Speed is the distance travelled by body in per unit time.

• Velocity is the Displacement covered by body in per unit time

• Average speed can never be zero while Average velocity can be zero.

• Velocity is vector quantity while speed is scalar quantity

• The rate of the change of Velocity is refered as Acceleration.

• Distance and speed is always positive.

• Velocity and displacement can either be positive or negative.

• The ratio between distance and displacement is 1:2.

• In a uniform circular motion speed remain Constant but velocity and acceleration changes time to time.