Calculate the acceleration produced in the direction of the resultant when two faces of magnitude 10N and 8N inclined at 60° act on a 0.4kg mass.
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RESULTANT FORCE
= R = √{ (10^2)+(8^2)+2(10)(8)(cos60°)}
=> R= √{100+64+80}
=> R= √(244) =15.620
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we know that Force = mass × acceleration
=> 15.620 = a × 0.4
=> a= 15.620/0.4 =39.05m/s^2
_______________________________
= R = √{ (10^2)+(8^2)+2(10)(8)(cos60°)}
=> R= √{100+64+80}
=> R= √(244) =15.620
________________________________
we know that Force = mass × acceleration
=> 15.620 = a × 0.4
=> a= 15.620/0.4 =39.05m/s^2
_______________________________
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meenakshi997sa:
is it correct??
I don't know, that's why I asked the question. But it seems accurate to me.
Thanks for the answer.
☺☺ welcome
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