Question

Calculate the acceleration produced in the direction of the resultant when two faces of magnitude 10N and 8N inclined at 60° act on a 0.4kg mass.

Answer 1

RESULTANT FORCE

= R = √{ (10^2)+(8^2)+2(10)(8)(cos60°)}

=> R= √{100+64+80}

=> R= √(244) =15.620

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we know that Force = mass × acceleration

=> 15.620 = a × 0.4

=> a= 15.620/0.4 =39.05m/s^2
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