Question

calculate the active mass of 15gm CH3COOH present in 2 litre solution?​

Answer 1

Answer:

Given mass = 15gm

Molecular mass = 60gm

Volume = 2l

Explanation:

Active mass =

$\frac{given \: mass}{molecular \: mass \times volume}$

= 15/60 *2

15/120

= 0.125gm

Answer 2

GIVEN MASS=15GM

MOLECULAR MASS=60 GM

VOLUME=2L..

REFER THE ATTACHMENT FOR SOLUTION...

MORE INFORMATION:

Active mass:

Active mass implies that amount of mass which is taking part in a reaction, that it is the effective concentration of a substance.It's other names are reactive mass or chemical activity.

Molecular mass:

the mass of a molecule that is equal to the sum of the masses of all the atoms contained in the molecule

VOLUME:

the quantity of three-dimensional space occupied by a liquid, solid, or gas.

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