Question

Calculate the actual volume of one molecule of water.​

Answer 1

Answer:

The number of moles in 1 litre = 1000 / 18.02 = 55.5 moles. 1 mole of water = 6.022 x 10^23 molecules of water, So 55.5 moles of water = 55.5 x 6.022 x 10^23 = 3.34 x 10^25 molecules of water. The gram molecular mass of water is 18.02. Thus volume occupied by 1 H2O molecule is 2.99 ×10-23 ml.

Answer 2

Q. Calculate the actual volume of one molecule of water.

$ans = 2.99 \times {10}^{ - 23} mol$

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Explanation:-

$density \: of \: water = 1g {ml}^{ - 1}$

$1g \: of \: water \: = 1ml$

$1mole \: of \: water \: = 18g \: of \: h2o$

$= 18 \: ml \: of \: water$

Therefore,

$6.022 \times {10}^{23} molecules \: of \: water \: occupy \: 18ml$

$1molecule \: of \: water \: occupy = \frac{18}{6.022 \times {10}^{23} }$

$= 2.99 \times {10}^{23} mol$