Chemistry, asked by titan87, 1 year ago

Calculate the actual volume of one molecule of water.​

Answers

Answered by pawankumar856
28

Answer:

The number of moles in 1 litre = 1000 / 18.02 = 55.5 moles. 1 mole of water = 6.022 x 10^23 molecules of water, So 55.5 moles of water = 55.5 x 6.022 x 10^23 = 3.34 x 10^25 molecules of water. The gram molecular mass of water is 18.02. Thus volume occupied by 1 H2O molecule is 2.99 ×10-23 ml.

Answered by Anonymous
58

Q. Calculate the actual volume of one molecule of water.

ans = 2.99 \times  {10}^{ - 23} mol

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Explanation:-

density \: of \: water = 1g {ml}^{ - 1}

1g \: of \: water \:  = 1ml

1mole \: of \: water \:  = 18g \: of \: h2o

 = 18 \: ml \: of \: water

Therefore,

6.022 \times  {10}^{23} molecules \: of \: water \: occupy \: 18ml

1molecule \: of \: water \: occupy =  \frac{18}{6.022 \times  {10}^{23} }

 = 2.99 \times  {10}^{23} mol

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